Some Help

[Blayde]

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I don't know what to do.

Find the area of an equilateral triangle with the sides 5 x sqrt(2) and another triangle with the sides (2x-1).


Also can someone see if I did this right.

An area of a square with the sides 3 x sqrt(5) and I got 45 mm ^2.

[Peace Frog]

Alright, pretty simple. Drop an immaginary line from the top of each triangle down to the base and you will devide it equaly in to two triangles.

From there it should be easy to find.


second triangle you do the same thing. I end up with a trinomial over two, but you can run that through the quadratic formula to come up with something a little more concise.

quadratic x=-b +/- [(b^2-4ac)^-2]/2a

Happy plugging and chugging


<happy>

[Six Pack]

Triangles were never my thing. But if you ever need help with rhombus, come see me. Rhombus, oh yea, that sounds hot.

[Blayde]

Originally Posted by Peace Frog

Alright, pretty simple. Drop an immaginary line from the top of each triangle down to the base and you will devide it equaly in to two triangles.

From there it should be easy to find.


second triangle you do the same thing. I end up with a trinomial over two, but you can run that through the quadratic formula to come up with something a little more concise.

quadratic x=-b +/- [(b^2-4ac)^-2]/2a

Happy plugging and chugging


<happy>

Okk, thanks, it helped.

Originally Posted by Six Pack

Triangles were never my thing. But if you ever need help with rhombus, come see me. Rhombus, oh yea, that sounds hot.

Ughh.. ok?

[Fearless™]

Originally Posted by Blayde

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I don't know what to do.

Find the area of an equilateral triangle with the sides 5 x sqrt(2) and another triangle with the sides (2x-1).


Also can someone see if I did this right.

An area of a square with the sides 3 x sqrt(5) and I got 45 mm ^2.

Equilateral triangles all have 60º angles...So using the area rule...
1) Area = ½ x 5√2 x 5√2 x sin 60º
...........= 21,65 mm²

2) Area = ½ x (2x - 1)² x sin 60º
...........= √3/4 (4x² +1 - 4x)
...........= √3 (x² + 1/4 -x)

You did the last one right.

[Blayde]

Originally Posted by Fearless Virgin

Equilateral triangles all have 60º angles...So using the area rule...
1) Area = ½ x 5√2 x 5√2 x sin 60º
...........= 21,65 mm²

2) Area = ½ x (2x - 1)² x sin 60º
...........= √3/4 (4x² +1 - 4x)
...........= √3 (x² + 1/4 -x)

You did the last one right.

Thanks..


Someone close this thread. I've got what I needed.

Thanks again

*Pms a mod*